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debug simplify_clause
Signed-off-by: Nikolaj Bjorner <nbjorner@microsoft.com>
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3 changed files with 43 additions and 1 deletions
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@ -40,6 +40,21 @@ Notes:
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==> drop 294 because it implies 295
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==> drop 292 because it implies 295
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TODO from bench0:
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-43 \/ 3 \/ 4 \/ -0 \/ -44 \/ -52
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-43: v3 + -1 != 0
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3: v3 == 0
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4: v3 <= v5
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-0: v5 + v4*v3 + -1*v2*v1 != 0
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-44: v4 + -1 != 0
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-52: v2 != 0
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Drop v3 == 0 because it implies v3 - 1 != 0
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The try_recognize_bailout returns true, but fails to simplify any other literal.
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Overall, why return true immediately if there are other literals that subsume each-other?
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--*/
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#include "math/polysat/solver.h"
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#include "math/polysat/simplify_clause.h"
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@ -110,6 +125,8 @@ namespace polysat {
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});
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}
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}
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if (j == cl.size())
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return false;
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cl.m_literals.shrink(j);
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return true;
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}
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@ -890,8 +890,10 @@ namespace polysat {
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UNREACHABLE();
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}
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}
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for (auto cl : side_lemmas)
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for (auto cl : side_lemmas) {
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m_simplify_clause.apply(*cl);
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add_clause(*cl);
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}
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SASSERT(lemma_invariant_part2(lemma_invariant_todo));
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learn_lemma(lemma);
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}
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