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Jakob Rath 2022-09-27 18:00:30 +02:00
parent 0f993e3977
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src/math/polysat/simplify_clause.cpp
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@ -11,33 +11,44 @@ Author:
Notes:
TODO: check why it fails with test_l2
at least 7 should be subsumed by 8 ??? (or the other way around)
and 6 should also be subsumed (but there's a difference in coefficient)
Lemma: 7 -6 -0 8 -1
7: -1 <= 2*v1 + 2 [ bvalue=l_false @1 pwatched=0 ]
-6: v1 + -1 != 0 [ bvalue=l_false @1 pwatched=0 ]
-0: v1 + 2*v0 + 1 != 0 [ bvalue=l_false @0 pwatched=1 ]
8: 1 <= 2*v1 + 2 [ bvalue=l_false @1 pwatched=0 ]
-1: 2*v1 + v0 != 0 [ bvalue=l_false @0 pwatched=1 ]
TODO: check why it fails with test_l2 (mod 2^2)
Lemma: -0 \/ -1 \/ -6 \/ 8
-0: v1 + 2*v0 + 1 != 0 [ l_false assert@0 pwatched ]
-1: 2*v1 + v0 != 0 [ l_false assert@0 pwatched ]
-6: v1 + -1 != 0 [ l_undef ]
8: 1 <= 2*v1 + 2 [ l_undef ]
-6 ==> v1 \not\in { 1 }
8 ==> v1 \not\in { 1, 3 }
so 8 subsumes -6 (8 ==> -6)
Actually:
- this means we have to keep -6 and throw out 8.
- because in case of v1 := 3, the original lemma will be satisfied.
TODO: meaning of "subsumption" is probably flipped in the code below?
TODO: from test_l5, conflict #2: (mod 2^3)
Lemma: -1 \/ -2 \/ -6 \/ -7
-1: 2*v1 + v0 + 4 != 0 [ bvalue=l_false @0 pwatched=1 ]
-2: 4*v1 + v0 + 4 != 0 [ bvalue=l_false @0 pwatched=1 ]
-6: 2*v1 + -2 != 0 [ bvalue=l_undef pwatched=0 ]
-7: v1 + -1 != 0 [ bvalue=l_undef pwatched=0 ]
-1: 2*v1 + v0 + 4 != 0 [ bvalue=l_false @0 pwatched=1 ]
-2: 4*v1 + v0 + 4 != 0 [ bvalue=l_false @0 pwatched=1 ]
-6: 2*v1 + -2 != 0 [ bvalue=l_undef pwatched=0 ]
-7: v1 + -1 != 0 [ bvalue=l_undef pwatched=0 ]
-7 ==> v1 \not\in { 1 }
-6 ==> v1 \not\in { 1, 5 }
==> -6 subsumes -7
TODO: from test_ineq_basic5:
TODO: from test_ineq_basic5: (mod 2^4)
Lemma: -0 \/ -1 \/ 2 \/ 3
-0: -4 > v1 + v0 [ bvalue=l_false @0 pwatched=1 ]
-1: v1 > 2 [ bvalue=l_false @0 pwatched=1 ]
2: -3 <= -1*v0 + -7 [ bvalue=l_undef pwatched=0 ]
3: -4 <= v0 [ bvalue=l_undef pwatched=0 ]
-0: -4 > v1 + v0 [ bvalue=l_false @0 pwatched=1 ]
-1: v1 > 2 [ bvalue=l_false @0 pwatched=1 ]
2: -3 <= -1*v0 + -7 [ bvalue=l_undef pwatched=0 ]
3: -4 <= v0 [ bvalue=l_undef pwatched=0 ]
2 ==> v0 \not\in [0;12[
3 ==> v0 \not\in [13;10[
A value is "truly" forbidden if neither branch works:
v0 \not\in [0;12[ intersect [13;10[ == [0;10[
==> replace 2, 3 by single constraint 10 <= v0
--*/
#include "math/polysat/solver.h"