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Address PR feedback on derive, nullability, and requested reverts
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8 changed files with 144 additions and 278 deletions
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@ -3120,104 +3120,6 @@ expr_ref seq_rewriter::merge_regex_sets(expr* r1, expr* r2, expr* unit,
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return composeresult(ar);
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}
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}
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expr_ref seq_rewriter::mk_regex_reverse(expr* r) {
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expr* r1 = nullptr, * r2 = nullptr, * c = nullptr;
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unsigned lo = 0, hi = 0;
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expr_ref result(m());
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if (re().is_empty(r) || re().is_range(r) || re().is_epsilon(r) || re().is_full_seq(r) ||
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re().is_full_char(r) || re().is_dot_plus(r) || re().is_of_pred(r))
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result = r;
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else if (re().is_to_re(r))
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result = re().mk_reverse(r);
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else if (re().is_reverse(r, r1))
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result = r1;
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else if (re().is_concat(r, r1, r2))
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result = mk_regex_concat(mk_regex_reverse(r2), mk_regex_reverse(r1));
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else if (m().is_ite(r, c, r1, r2))
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result = m().mk_ite(c, mk_regex_reverse(r1), mk_regex_reverse(r2));
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else if (re().is_union(r, r1, r2)) {
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// enforce deterministic evaluation order
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auto a1 = mk_regex_reverse(r1);
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auto b1 = mk_regex_reverse(r2);
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result = re().mk_union(a1, b1);
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}
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else if (re().is_intersection(r, r1, r2)) {
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auto a1 = mk_regex_reverse(r1);
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auto b1 = mk_regex_reverse(r2);
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result = re().mk_inter(a1, b1);
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}
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else if (re().is_diff(r, r1, r2)) {
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auto a1 = mk_regex_reverse(r1);
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auto b1 = mk_regex_reverse(r2);
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result = re().mk_diff(a1, b1);
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}
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else if (re().is_xor(r, r1, r2)) {
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auto a1 = mk_regex_reverse(r1);
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auto b1 = mk_regex_reverse(r2);
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result = re().mk_xor(a1, b1);
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}
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else if (re().is_star(r, r1))
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result = re().mk_star(mk_regex_reverse(r1));
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else if (re().is_plus(r, r1))
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result = re().mk_plus(mk_regex_reverse(r1));
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else if (re().is_loop(r, r1, lo))
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result = re().mk_loop(mk_regex_reverse(r1), lo);
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else if (re().is_loop(r, r1, lo, hi))
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result = re().mk_loop_proper(mk_regex_reverse(r1), lo, hi);
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else if (re().is_opt(r, r1))
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result = re().mk_opt(mk_regex_reverse(r1));
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else if (re().is_complement(r, r1))
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result = re().mk_complement(mk_regex_reverse(r1));
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else
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//stuck cases: such as r being a regex variable
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//observe that re().mk_reverse(to_re(s)) is not a stuck case
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result = re().mk_reverse(r);
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return result;
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}
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expr_ref seq_rewriter::mk_regex_concat(expr* r, expr* s) {
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sort* seq_sort = nullptr, * ele_sort = nullptr;
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VERIFY(m_util.is_re(r, seq_sort));
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VERIFY(u().is_seq(seq_sort, ele_sort));
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SASSERT(r->get_sort() == s->get_sort());
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expr_ref result(m());
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expr* r1, * r2;
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if (re().is_epsilon(r) || re().is_empty(s))
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result = s;
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else if (re().is_epsilon(s) || re().is_empty(r))
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result = r;
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else if (re().is_full_seq(r) && re().is_full_seq(s))
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result = r;
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else if (re().is_full_char(r) && re().is_full_seq(s))
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// ..* = .+
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result = re().mk_plus(re().mk_full_char(ele_sort));
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else if (re().is_full_seq(r) && re().is_full_char(s))
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// .*. = .+
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result = re().mk_plus(re().mk_full_char(ele_sort));
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else if (re().is_concat(r, r1, r2))
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// create the resulting concatenation in right-associative form except for the following case
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// TODO: maintain the following invariant for A ++ B{m,n} + C
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// concat(concat(A, B{m,n}), C) (if A != () and C != ())
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// concat(B{m,n}, C) (if A == () and C != ())
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// where A, B, C are regexes
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// Using & below for Intersection and | for Union
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// In other words, do not make A ++ B{m,n} into right-assoc form, but keep B{m,n} at the top
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// This will help to identify this situation in the merge routine:
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// concat(concat(A, B{0,m}), C) | concat(concat(A, B{0,n}), C)
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// simplifies to
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// concat(concat(A, B{0,max(m,n)}), C)
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// analogously:
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// concat(concat(A, B{0,m}), C) & concat(concat(A, B{0,n}), C)
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// simplifies to
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// concat(concat(A, B{0,min(m,n)}), C)
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result = mk_regex_concat(r1, mk_regex_concat(r2, s));
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else {
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result = re().mk_concat(r, s);
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}
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return result;
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}
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/*
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* calls elim_condition
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*/
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